c^2+5/6c=+1/6

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Solution for c^2+5/6c=+1/6 equation: 



c^2+5/6c=+1/6

We move all terms to the left:

c^2+5/6c-(+1/6)=0



Domain of the equation: 6c!=0

c!=0/6

c!=0

c∈R



We get rid of parentheses

c^2+5/6c-1/6=0

We calculate fractions


c^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{2}=0$

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